C and strings

[wmHardRock]

Hel
Hi, guys. I have a little C program that asks for a name (support for white character), but when I print it, it also displays the return caracter. So if in input Vince, it would return something like:
Hello Vince
, how's it going?

How can I prevent that?

[Verbed]

The return ( \r ) should be the last character in the string before the null terminating character ( \0 ). So, if the string was defined as an array ( char string[...] ), this should work:

string[strlen(string) - 1] = '\0';

[wmHardRock]

#include <stdio.h>
#include <string.h>

main()
{
char nom[40];

printf("Salut! C'est quoi ton nom? ");
fgets(nom,40,stdin);
printf("Hyas %s! Comment ça va?",nom);
}


how'd you fix that?

[Strike]

#include <stdio.h>
#include <string.h>

#define STRING_LENGTH 40

main ()
{
char nom[STRING_LENGTH];
printf("Salut! C'est quoi ton nom? ");
fgets(nom, STRING_LENGTH, stdin);
nom[STRING_LENGTH - 1] = '\0';
printf("Hyas %s! Comment ça va?",nom);
}

That's one way to do it (I like anything that acts as the size of an array to be a #define so I can change all instances of it later without having to hunt for numbers).

----edit----
Actually, that doesn't work. It might have to do with flushing buffers or something like that ... that's weird.

[This message has been edited by Strike (edited 14 November 2000).]

[miller]

Strike:

The reason that doesn't work is because the end of the string isn't neccessarily at char 40.

wmHardRock:
You need to do a:

string[strlen(string) -1] = '\0';

like Verbed said.


Even better, since the name might or might not have the '\n' at the end:


if(string[strlen(string)-1] == '\n')
string[strlen(string)-1] = '\0';