char problem in C

[Seko]

i have a char array: char x[20];
i did the following: strcpy(x, argv[2]);

but i want to add one space in the begining and end of the char array for example say argv[2] is "abc" so i want x to contain " abc " how can i do this?

thx

[Minime80]

this should pretty much do it
char x[20];
strcpy(x, " ");
strcat(x, argv[2]);
strcat(x, " ");

[Seko]

Thx very much i could not think of it :) anyway i am new to C programming....

[Minime80]

Anytime. We're here to help.

[CyberCoder]

another way to do that:
int x[20];
sprintf(x," %s ",argv[2]);

[dchidelf]

or

char x[20];
sprintf(x," %.17s ",argv[2]);


That should ensure the string will actually fit within the allocated space.

[Seko]

Wow prety much C coders here...i want to be a good C coder too thx for different technics..By the way another question i have in the forum about exec()....

take a look:)

[bwkaz]

Or

char x[20];

snprintf(x, 20, " %s ", argv[2]); (another way to not overflow the buffer).