Bash question..

[goon12]

I have googled a bit and checkd the NHF's. How in Bash can you check 2 condition...

if [ $foo -ne "30" && $boo -eq "30" ]
then
commands...
fi

I know that's not right cause it's working, just wondering how I would do something like that?

Thanks,
goon12

[goon12]

Sorry I found it 1 minute after I posted

[bsh152s]

For those searching the forums later, the correct fix is using double brackets.


if [[ $foo -ne "30" && $boo -eq "30" ]]
then
commands...
fi

[bwkaz]

But:

if [ $foo -ne 30 -a $boo -eq 30 ]
then
commands...
fi is portable to shells other than bash. I don't think the original Bourne shell (/bin/sh) knows how to parse double square brackets (though of course I haven't tried it). A single square bracket is equivalent to /bin/test, usually (unless your shell treats it as a builtin), since you have a symlink from /bin/[ to /bin/test.

/bin/test knows that -a means "and", and -o means "or".

[bsh152s]

Good info to know. All in all, even if you solve the problem yourself, post the solution.

[goon12]

Weird.. I was using this and it seemed to work

if [ $upalert -eq "1" ] && [ $res -eq "30" ]
then
...
fi


Either way, Thanks.

[bwkaz]

Oh, right, if understands &&. I don't know for sure if all Bourne shells' if's understand &&, though... they might.